7c^2+17c+10=0

Solution for 7c^2+17c+10=0 equation:

7c^2+17c+10=0

a = 7; b = 17; c = +10;
Δ = b2-4ac
Δ = 172-4·7·10
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-3}{2*7}=\frac{-20}{14}
=-1+3/7
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+3}{2*7}=\frac{-14}{14}
=-1
$